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Edit history of sicp-ex-2.17

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172013-07-19 22:52:35+1 -2 line(s)[View this version, source] [Diff to previous]
fix comment format
162013-07-19 22:49:39+2 -1 line(s)[View this version, source] [Diff to current|previous]
not cdr, but a full iteration of length
152013-07-19 22:48:24+1 -1 line(s)[View this version, source] [Diff to current|previous]
precision for comment on length
142013-07-19 22:46:08+3 -0 line(s)[View this version, source] [Diff to current|previous]
made a comment about the use of length
132013-03-06 18:23:50+14 -9 line(s)[View this version, source] [Diff to current|previous]
include correct solution in the main page
122013-01-08 14:33:24+1 -2 line(s)[View this version, source] [Diff to current|previous]
Changed text in my post for better readability.
112013-01-08 13:23:15+27 -0 line(s)[View this version, source] [Diff to current|previous]
Added my solution to exercise 2.17. Daniel-Aamariei
102012-11-26 16:33:48+7 -0 line(s)[View this version, source] [Diff to current|previous]
Added links at the top to previous exercises / index / next exercises
92012-09-09 05:26:50+10 -0 line(s)[View this version, source] [Diff to current|previous]
Another solution -- shubhro
82011-12-20 09:05:54+17 -0 line(s)[View this version, source] [Diff to current|previous]
All answers already committed do not return the value as a list. The exercise is to define a procedure that returns a list.
72011-09-09 02:27:55+9 -0 line(s)[View this version, source] [Diff to current|previous]
simple solution
62011-02-06 00:51:52+9 -0 line(s)[View this version, source] [Diff to current|previous]
same as EcsCodes, but passes test for empty list
52010-07-25 21:30:45+5 -1 line(s)[View this version, source] [Diff to current|previous]
List pair with Helper (ref lst x)
42010-07-25 21:27:36+13 -0 line(s)[View this version, source] [Diff to current|previous]
Exercise 2.17 EcsCodes returns only last item
32010-07-20 10:34:53+10 -0 line(s)[View this version, source] [Diff to current|previous]
<<<EcsCodes {{{scheme A simple but ingenious code (define(lastPair L) (if(=(length L)1) (car L) (lastPair (cdr L)))) }}}
22009-09-30 21:32:30+13 -0 line(s)[View this version, source] [Diff to current|previous]
another solution
12007-12-25 19:11:33+17 -0 line(s)[View this version, source] [Diff to current|previous]
initial draft
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