<< Previous exercise (2.88) | Index | Next exercise (2.90) >>

;; an even shorter solution to achieve the same result (define (first-term term-list) (make-term (- (len term-list) 1) (car term-list))) (define (adjoin-term term term-list) (cond ((=zero? term) term-list) ((=equ? (order term) (length term-list)) (cons (coeff term) term-list)) (else (adjoin-term term (cons 0 term-list)))))

We don't need to change much. Also, since adjoin-term is properly used in add-term and mul-term, I don't think we have to change it drastically like some people did.

;; List the term, and find the order (define (first-term term-list) (list (car term-list) ; first term (- 1 (length term-list)))) ; order is length-1 (we index polynomials from 0) ;; Slightly modified to cons the coeff instead of the actual term (define (adjoin-term term term-list) (let ((coeff-of-term (coeff term))) (if (=zero? coeff-of-term) term-list (cons coeff-of-term term-list))))

It is probably me, but none of the solution above worked for me.

meteorgan's solution has bracketing errors and even after fixing them there seems to be logical errors.

hattivat uses =zero? directly on term which does not work because add-terms calls adjoin-term on regular terms, i.e. one that have coeff and order.

Finally, Marisa's solution runs, but creates false results for my tests.

The following code worked for me when I added it to the poly-package from the book. Note that not considering zero terms would yield invalid results for multiplication.

(define (first-term term-list) (make-term (- (length term-list) 1) (car term-list))) (define (adjoin-term term term-list) (let ((coeff-term (coeff term)) (order-term (order term)) (length-terms (length term-list))) (cond ((= order-term length-terms) (cons coeff-term term-list)) ((< order-term length-terms) (error "Cannot adjoin lower-order term to terms")) (else (cons coeff-term (adjoin-term (make-term (- order-term 1) 0) term-list))))))

meteorgan