sicp-ex-3.34



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meteorgan

  
  
 if given the following code: 
 (set-value! b 4 'user) 
 you will find that you can't get the value of a. Because in procedure multiplier, you only  have (has-value? b) true,  m1, m2 are not set, even they are the same, but multiplier doesn't know that.