The modified version of `expmod` computes huge intermediate results.

Scheme is able to handle arbitrary-precision arithmetic, but arithmetic with arbitrarily long numbers is computationally expensive. This means that we get the same (correct) results, but it takes considerably longer.

For example:

(define (square m) (display "square ")(display m)(newline) (* m m)) => (expmod 5 101 101) square 5 square 24 square 71 square 92 square 1 square 1 5 => (remainder (fast-expt 5 101) 101) square 5 square 25 square 625 square 390625 square 152587890625 square 23283064365386962890625 5

The `remainder` operation inside the original `expmod` implementation, keeps the numbers being squared less than the number tested for primality `m`. `fast-expt` however squares huge numbers of `a^m` size.

<< Previous exercise (1.24) | sicp-solutions | Next exercise (1.26) >>