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(define sum 0) ;; sum => 0 (define (accum x) (set! sum (+ x sum)) sum) ;; sum => 0 (define seq (stream-map accum (stream-enumerate-interval 1 20))) ;; sum => 1 (define y (stream-filter even? seq)) ;; sum => 6 (define z (stream-filter (lambda (x) (= (remainder x 5) 0)) seq)) ;; sum => 10 (stream-ref y 7) ;; sum => 136 ;; => 136 (display-stream z) ;; sum => 210 ;; => (10 15 45 55 105 120 190 210)

If we had not memoized the results of delayed evaluations, we would need to recalculate the elements that `stream-ref' created when we were evaluating `display-stream'. Thus, the results would be different, because the accumulator would add those to the sum twice.

perry